39(x+5)=2(3x+12)

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Solution for 39(x+5)=2(3x+12) equation: 



39(x+5)=2(3x+12)

We move all terms to the left:

39(x+5)-(2(3x+12))=0

We multiply parentheses

39x-(2(3x+12))+195=0



We calculate terms in parentheses: -(2(3x+12)), so:

2(3x+12)

We multiply parentheses

6x+24

Back to the equation:

-(6x+24)



We get rid of parentheses

39x-6x-24+195=0

We add all the numbers together, and all the variables

33x+171=0

We move all terms containing x to the left, all other terms to the right

33x=-171

x=-171/33

x=-5+2/11

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