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38x^2-10x-75=0
a = 38; b = -10; c = -75;
Δ = b2-4ac
Δ = -102-4·38·(-75)
Δ = 11500
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11500}=\sqrt{100*115}=\sqrt{100}*\sqrt{115}=10\sqrt{115}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{115}}{2*38}=\frac{10-10\sqrt{115}}{76} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{115}}{2*38}=\frac{10+10\sqrt{115}}{76} $
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