38x+40+120x=34x-7(20+x)

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Solution for 38x+40+120x=34x-7(20+x) equation: 



38x+40+120x=34x-7(20+x)

We move all terms to the left:

38x+40+120x-(34x-7(20+x))=0

We add all the numbers together, and all the variables

38x+120x-(34x-7(x+20))+40=0

We add all the numbers together, and all the variables

158x-(34x-7(x+20))+40=0



We calculate terms in parentheses: -(34x-7(x+20)), so:

34x-7(x+20)

We multiply parentheses

34x-7x-140

We add all the numbers together, and all the variables

27x-140

Back to the equation:

-(27x-140)



We get rid of parentheses

158x-27x+140+40=0

We add all the numbers together, and all the variables

131x+180=0

We move all terms containing x to the left, all other terms to the right

131x=-180

x=-180/131

x=-1+49/131

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