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384=x(x-4)
We move all terms to the left:
384-(x(x-4))=0
We calculate terms in parentheses: -(x(x-4)), so:We get rid of parentheses
x(x-4)
We multiply parentheses
x^2-4x
Back to the equation:
-(x^2-4x)
-x^2+4x+384=0
We add all the numbers together, and all the variables
-1x^2+4x+384=0
a = -1; b = 4; c = +384;
Δ = b2-4ac
Δ = 42-4·(-1)·384
Δ = 1552
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1552}=\sqrt{16*97}=\sqrt{16}*\sqrt{97}=4\sqrt{97}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(4)-4\sqrt{97}}{2*-1}=\frac{-4-4\sqrt{97}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(4)+4\sqrt{97}}{2*-1}=\frac{-4+4\sqrt{97}}{-2} $
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