38/72=(2x+1)/4x

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Solution for 38/72=(2x+1)/4x equation: 



38/72=(2x+1)/4x

We move all terms to the left:

38/72-((2x+1)/4x)=0



Domain of the equation: 4x)!=0

x!=0/1

x!=0

x∈R



We calculate fractions


(-((2x+1)*72)/4x*72)+152x/4x*72)=0



We calculate terms in parentheses: +(-((2x+1)*72)/4x*72), so:

-((2x+1)*72)/4x*72

We multiply all the terms by the denominator


-((2x+1)*72)



We calculate terms in parentheses: -((2x+1)*72), so:

(2x+1)*72

We multiply parentheses

144x+72

Back to the equation:

-(144x+72)



We get rid of parentheses

-144x-72

Back to the equation:

+(-144x-72)



We get rid of parentheses

-144x+152x/4x*72)-72=0

We multiply all the terms by the denominator


-144x*4x*72)-72+152x=0

Wy multiply elements

-41472x^3*7=0

We do not support expression: x^3

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