37-2(4z+1)=3(5z+4)

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Solution for 37-2(4z+1)=3(5z+4) equation: 



37-2(4z+1)=3(5z+4)

We move all terms to the left:

37-2(4z+1)-(3(5z+4))=0

We multiply parentheses

-8z-(3(5z+4))-2+37=0



We calculate terms in parentheses: -(3(5z+4)), so:

3(5z+4)

We multiply parentheses

15z+12

Back to the equation:

-(15z+12)



We add all the numbers together, and all the variables

-8z-(15z+12)+35=0

We get rid of parentheses

-8z-15z-12+35=0

We add all the numbers together, and all the variables

-23z+23=0

We move all terms containing z to the left, all other terms to the right

-23z=-23

z=-23/-23

z=1

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