37-(3x+5)=9x-8(x-3)

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Solution for 37-(3x+5)=9x-8(x-3) equation: 



37-(3x+5)=9x-8(x-3)

We move all terms to the left:

37-(3x+5)-(9x-8(x-3))=0

We get rid of parentheses

-3x-(9x-8(x-3))-5+37=0



We calculate terms in parentheses: -(9x-8(x-3)), so:

9x-8(x-3)

We multiply parentheses

9x-8x+24

We add all the numbers together, and all the variables

x+24

Back to the equation:

-(x+24)



We add all the numbers together, and all the variables

-3x-(x+24)+32=0

We get rid of parentheses

-3x-x-24+32=0

We add all the numbers together, and all the variables

-4x+8=0

We move all terms containing x to the left, all other terms to the right

-4x=-8

x=-8/-4

x=+2

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