36x2-60x+16=0

Solution for 36x2-60x+16=0 equation:

36x^2-60x+16=0

a = 36; b = -60; c = +16;
Δ = b2-4ac
Δ = -602-4·36·16
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-60)-36}{2*36}=\frac{24}{72}
=1/3
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-60)+36}{2*36}=\frac{96}{72}
=1+1/3
$