36x2+72x+35=0

Solution for 36x2+72x+35=0 equation:

36x^2+72x+35=0

a = 36; b = 72; c = +35;
Δ = b2-4ac
Δ = 722-4·36·35
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(72)-12}{2*36}=\frac{-84}{72}
=-1+1/6
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(72)+12}{2*36}=\frac{-60}{72}
=-5/6
$