36p-7p=-7p(p-5)

Solution for 36p-7p=-7p(p-5) equation:

36p-7p=-7p(p-5)

We move all terms to the left:

36p-7p-(-7p(p-5))=0

We add all the numbers together, and all the variables

29p-(-7p(p-5))=0


We calculate terms in parentheses: -(-7p(p-5)), so:

-7p(p-5)

We multiply parentheses

-7p^2+35p

Back to the equation:

-(-7p^2+35p)


We get rid of parentheses

7p^2-35p+29p=0

We add all the numbers together, and all the variables

7p^2-6p=0

a = 7; b = -6; c = 0;
Δ = b2-4ac
Δ = -62-4·7·0
Δ = 36
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{36}=6$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6)-6}{2*7}=\frac{0}{14}
=0
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6)+6}{2*7}=\frac{12}{14}
=6/7
$