36n2+5=41

Solution for 36n2+5=41 equation:

36n^2+5=41

We move all terms to the left:

36n^2+5-(41)=0

We add all the numbers together, and all the variables

36n^2-36=0

a = 36; b = 0; c = -36;
Δ = b2-4ac
Δ = 02-4·36·(-36)
Δ = 5184
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{5184}=72$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-72}{2*36}=\frac{-72}{72}
=-1
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+72}{2*36}=\frac{72}{72}
=1
$