363=3f2

Solution for 363=3f2 equation:

363=3f^2

We move all terms to the left:

363-(3f^2)=0

a = -3; b = 0; c = +363;
Δ = b2-4ac
Δ = 02-4·(-3)·363
Δ = 4356
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4356}=66$
$f_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-66}{2*-3}=\frac{-66}{-6}
=+11
$
$f_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+66}{2*-3}=\frac{66}{-6}
=-11
$