360=40+(1/3*x)+(x-10)+(x-20)

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Solution for 360=40+(1/3*x)+(x-10)+(x-20) equation: 



360=40+(1/3x)+(x-10)+(x-20)

We move all terms to the left:

360-(40+(1/3x)+(x-10)+(x-20))=0



Domain of the equation: 3x)+(x-10)+(x-20))!=0

x∈R



We add all the numbers together, and all the variables

-(40+(+1/3x)+(x-10)+(x-20))+360=0

We multiply all the terms by the denominator


-(40+(+1+360*3x)+(x-10)+(x-20))=0



We calculate terms in parentheses: -(40+(+1+360*3x)+(x-10)+(x-20)), so:

40+(+1+360*3x)+(x-10)+(x-20)

determiningTheFunctionDomain
(+1+360*3x)+(x-10)+(x-20)+40

We add all the numbers together, and all the variables

(360*3x+1)+(x-10)+(x-20)+40

We get rid of parentheses

360*3x+x+x+1-10-20+40

We add all the numbers together, and all the variables

2x+360*3x+11

Wy multiply elements

2x+1080x+11

We add all the numbers together, and all the variables

1082x+11

Back to the equation:

-(1082x+11)



We get rid of parentheses

-1082x-11=0

We move all terms containing x to the left, all other terms to the right

-1082x=11

x=11/-1082

x=-11/1082

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