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360=2x+4/3x
We move all terms to the left:
360-(2x+4/3x)=0
Domain of the equation: 3x)!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
-(+2x+4/3x)+360=0
We get rid of parentheses
-2x-4/3x+360=0
We multiply all the terms by the denominator
-2x*3x+360*3x-4=0
Wy multiply elements
-6x^2+1080x-4=0
a = -6; b = 1080; c = -4;
Δ = b2-4ac
Δ = 10802-4·(-6)·(-4)
Δ = 1166304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1166304}=\sqrt{16*72894}=\sqrt{16}*\sqrt{72894}=4\sqrt{72894}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1080)-4\sqrt{72894}}{2*-6}=\frac{-1080-4\sqrt{72894}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1080)+4\sqrt{72894}}{2*-6}=\frac{-1080+4\sqrt{72894}}{-12} $
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