360=1/2x+(x-35)+x+(x-49)

Solution for 360=1/2x+(x-35)+x+(x-49) equation:

360=1/2x+(x-35)+x+(x-49)

We move all terms to the left:

360-(1/2x+(x-35)+x+(x-49))=0


Domain of the equation: 2x+(x-35)+x+(x-49))!=0

x∈R


We multiply all the terms by the denominator


-(1+360*2x+(x-35)+x+(x-49))=0


We calculate terms in parentheses: -(1+360*2x+(x-35)+x+(x-49)), so:

1+360*2x+(x-35)+x+(x-49)

determiningTheFunctionDomain
360*2x+(x-35)+x+(x-49)+1

We add all the numbers together, and all the variables

x+360*2x+(x-35)+(x-49)+1

Wy multiply elements

x+720x+(x-35)+(x-49)+1

We get rid of parentheses

x+720x+x+x-35-49+1

We add all the numbers together, and all the variables

723x-83

Back to the equation:

-(723x-83)


We get rid of parentheses

-723x+83=0

We move all terms containing x to the left, all other terms to the right

-723x=-83

x=-83/-723

x=83/723