360=(x+20)+(x+5)+(x-5)+(x+10)

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Solution for 360=(x+20)+(x+5)+(x-5)+(x+10) equation: 



360=(x+20)+(x+5)+(x-5)+(x+10)

We move all terms to the left:

360-((x+20)+(x+5)+(x-5)+(x+10))=0



We calculate terms in parentheses: -((x+20)+(x+5)+(x-5)+(x+10)), so:

(x+20)+(x+5)+(x-5)+(x+10)

We get rid of parentheses

x+x+x+x+20+5-5+10

We add all the numbers together, and all the variables

4x+30

Back to the equation:

-(4x+30)



We get rid of parentheses

-4x-30+360=0

We add all the numbers together, and all the variables

-4x+330=0

We move all terms containing x to the left, all other terms to the right

-4x=-330

x=-330/-4

x=82+1/2

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