360=(6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11)

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Solution for 360=(6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11) equation: 



360=(6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11)

We move all terms to the left:

360-((6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11))=0



We calculate terms in parentheses: -((6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11)), so:

(6x+2)+(x-3)+(3x-5)+(2x+7)+(x+11)

We get rid of parentheses

6x+x+3x+2x+x+2-3-5+7+11

We add all the numbers together, and all the variables

13x+12

Back to the equation:

-(13x+12)



We get rid of parentheses

-13x-12+360=0

We add all the numbers together, and all the variables

-13x+348=0

We move all terms containing x to the left, all other terms to the right

-13x=-348

x=-348/-13

x=26+10/13

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