3600=(500+x)+(3x)+(x)

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Solution for 3600=(500+x)+(3x)+(x) equation: 



3600=(500+x)+(3x)+(x)

We move all terms to the left:

3600-((500+x)+(3x)+(x))=0

We add all the numbers together, and all the variables

-((x+500)+3x+x)+3600=0



We calculate terms in parentheses: -((x+500)+3x+x), so:

(x+500)+3x+x

We add all the numbers together, and all the variables

4x+(x+500)

We get rid of parentheses

4x+x+500

We add all the numbers together, and all the variables

5x+500

Back to the equation:

-(5x+500)



We get rid of parentheses

-5x-500+3600=0

We add all the numbers together, and all the variables

-5x+3100=0

We move all terms containing x to the left, all other terms to the right

-5x=-3100

x=-3100/-5

x=+620

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