36/27=x+5/x

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Solution for 36/27=x+5/x equation: 


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

36/27 = x+5/x // - x+5/x

36/27-x-(5/x) = 0

36/27-x-5*x^-1 = 0

4/3*x^0-1*x^1-5*x^-1 = 0

(4/3*x^1-1*x^2-5*x^0)/(x^1) = 0 // * x^2

x^1*(4/3*x^1-1*x^2-5*x^0) = 0

x^1

(4/3)*x-x^2-5 = 0

(4/3)*x-x^2-5 = 0

DELTA = (4/3)^2-(-5*(-1)*4)

DELTA = -164/9

DELTA < 0

x in { } 

x belongs to the empty set

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