36/12=(32-x)/x

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Solution for 36/12=(32-x)/x equation: 



36/12=(32-x)/x

We move all terms to the left:

36/12-((32-x)/x)=0



Domain of the equation: x)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

-((-1x+32)/x)+36/12=0

We add all the numbers together, and all the variables

-((-1x+32)/x)+3=0

We multiply all the terms by the denominator


-((-1x+32)+3*x)=0



We calculate terms in parentheses: -((-1x+32)+3*x), so:

(-1x+32)+3*x

We add all the numbers together, and all the variables

3x+(-1x+32)

We get rid of parentheses

3x-1x+32

We add all the numbers together, and all the variables

2x+32

Back to the equation:

-(2x+32)



We get rid of parentheses

-2x-32=0

We move all terms containing x to the left, all other terms to the right

-2x=32

x=32/-2

x=-16

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