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36/(2x-3)=72/(2x+3)
We move all terms to the left:
36/(2x-3)-(72/(2x+3))=0
Domain of the equation: (2x-3)!=0
We move all terms containing x to the left, all other terms to the right
2x!=3
x!=3/2
x!=1+1/2
x∈R
Domain of the equation: (2x+3))!=0We calculate fractions
x∈R
72x/((2x-3)*(2x+3)))+(-(72*(2x-3))/((2x-3)*(2x+3)))=0
We calculate terms in parentheses: -(72*(2x-3))/((2x-3)*(2x+3))), so:We add all the numbers together, and all the variables
72*(2x-3))/((2x-3)*(2x+3))
We multiply all the terms by the denominator
72*(2x-3))
We multiply parentheses
144x+
We add all the numbers together, and all the variables
144x
Back to the equation:
-(144x)
-144x+72x/((2x-3)*(2x+3)))+(=0
We multiply all the terms by the denominator
-144x*((2x-3)*(2x+3)))+(+72x=0
We add all the numbers together, and all the variables
72x-144x*((2x-3)*(2x+3)))+(=0
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