36-16x-x2=0

Solution for 36-16x-x2=0 equation:

36-16x-x2=0

We add all the numbers together, and all the variables

-1x^2-16x+36=0

a = -1; b = -16; c = +36;
Δ = b2-4ac
Δ = -162-4·(-1)·36
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-20}{2*-1}=\frac{-4}{-2}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+20}{2*-1}=\frac{36}{-2}
=-18
$