36-1(2c+3)=2(c+4)+c

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Solution for 36-1(2c+3)=2(c+4)+c equation: 



36-1(2c+3)=2(c+4)+c

We move all terms to the left:

36-1(2c+3)-(2(c+4)+c)=0



We calculate terms in parentheses: -(2(c+4)+c), so:

2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We get rid of parentheses

-1(2c+3)-3c-8+36=0

We add all the numbers together, and all the variables

-3c-1(2c+3)+28=0

We move all terms containing c to the left, all other terms to the right

-3c-1(2c+3)=-28

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