36-(3c+4)=2(c+4)+c

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Solution for 36-(3c+4)=2(c+4)+c equation: 


Simplifying
36 + -1(3c + 4) = 2(c + 4) + c

Reorder the terms:
36 + -1(4 + 3c) = 2(c + 4) + c
36 + (4 * -1 + 3c * -1) = 2(c + 4) + c
36 + (-4 + -3c) = 2(c + 4) + c

Combine like terms: 36 + -4 = 32
32 + -3c = 2(c + 4) + c

Reorder the terms:
32 + -3c = 2(4 + c) + c
32 + -3c = (4 * 2 + c * 2) + c
32 + -3c = (8 + 2c) + c

Combine like terms: 2c + c = 3c
32 + -3c = 8 + 3c

Solving
32 + -3c = 8 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
32 + -3c + -3c = 8 + 3c + -3c

Combine like terms: -3c + -3c = -6c
32 + -6c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
32 + -6c = 8 + 0
32 + -6c = 8

Add '-32' to each side of the equation.
32 + -32 + -6c = 8 + -32

Combine like terms: 32 + -32 = 0
0 + -6c = 8 + -32
-6c = 8 + -32

Combine like terms: 8 + -32 = -24
-6c = -24

Divide each side by '-6'.
c = 4

Simplifying
c = 4

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