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36+6(x-7)=-3(1+3x)
We move all terms to the left:
36+6(x-7)-(-3(1+3x))=0
We add all the numbers together, and all the variables
6(x-7)-(-3(3x+1))+36=0
We multiply parentheses
6x-(-3(3x+1))-42+36=0
We calculate terms in parentheses: -(-3(3x+1)), so:We add all the numbers together, and all the variables
-3(3x+1)
We multiply parentheses
-9x-3
Back to the equation:
-(-9x-3)
6x-(-9x-3)-6=0
We get rid of parentheses
6x+9x+3-6=0
We add all the numbers together, and all the variables
15x-3=0
We move all terms containing x to the left, all other terms to the right
15x=3
x=3/15
x=1/5
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