36(3c+4)=2(c+4)+c

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Solution for 36(3c+4)=2(c+4)+c equation: 



36(3c+4)=2(c+4)+c

We move all terms to the left:

36(3c+4)-(2(c+4)+c)=0

We multiply parentheses

108c-(2(c+4)+c)+144=0



We calculate terms in parentheses: -(2(c+4)+c), so:

2(c+4)+c

We add all the numbers together, and all the variables

c+2(c+4)

We multiply parentheses

c+2c+8

We add all the numbers together, and all the variables

3c+8

Back to the equation:

-(3c+8)



We get rid of parentheses

108c-3c-8+144=0

We add all the numbers together, and all the variables

105c+136=0

We move all terms containing c to the left, all other terms to the right

105c=-136

c=-136/105

c=-1+31/105

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