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35x^2-63x+28=0
a = 35; b = -63; c = +28;
Δ = b2-4ac
Δ = -632-4·35·28
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{49}=7$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-63)-7}{2*35}=\frac{56}{70} =4/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-63)+7}{2*35}=\frac{70}{70} =1 $
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