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35x^2+19x+8=6
We move all terms to the left:
35x^2+19x+8-(6)=0
We add all the numbers together, and all the variables
35x^2+19x+2=0
a = 35; b = 19; c = +2;
Δ = b2-4ac
Δ = 192-4·35·2
Δ = 81
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{81}=9$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(19)-9}{2*35}=\frac{-28}{70} =-2/5 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(19)+9}{2*35}=\frac{-10}{70} =-1/7 $
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