35n2=22n=3=0

Solution for 35n2=22n=3=0 equation:

35n^2=22n=3=0

We move all terms to the left:

35n^2-(22n)=0

a = 35; b = -22; c = 0;
Δ = b2-4ac
Δ = -222-4·35·0
Δ = 484
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{484}=22$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-22}{2*35}=\frac{0}{70}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+22}{2*35}=\frac{44}{70}
=22/35
$