35n2+32n+3=0

Solution for 35n2+32n+3=0 equation:

35n^2+32n+3=0

a = 35; b = 32; c = +3;
Δ = b2-4ac
Δ = 322-4·35·3
Δ = 604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{604}=\sqrt{4*151}=\sqrt{4}*\sqrt{151}=2\sqrt{151}$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(32)-2\sqrt{151}}{2*35}=\frac{-32-2\sqrt{151}}{70}
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(32)+2\sqrt{151}}{2*35}=\frac{-32+2\sqrt{151}}{70}
$