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35=w*3w
We move all terms to the left:
35-(w*3w)=0
We add all the numbers together, and all the variables
-(+w*3w)+35=0
We get rid of parentheses
-w*3w+35=0
Wy multiply elements
-3w^2+35=0
a = -3; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·(-3)·35
Δ = 420
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{420}=\sqrt{4*105}=\sqrt{4}*\sqrt{105}=2\sqrt{105}$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{105}}{2*-3}=\frac{0-2\sqrt{105}}{-6} =-\frac{2\sqrt{105}}{-6} =-\frac{\sqrt{105}}{-3} $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{105}}{2*-3}=\frac{0+2\sqrt{105}}{-6} =\frac{2\sqrt{105}}{-6} =\frac{\sqrt{105}}{-3} $
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