35=9i-2(2-2i)

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Solution for 35=9i-2(2-2i) equation: 



35=9i-2(2-2i)

We move all terms to the left:

35-(9i-2(2-2i))=0

We add all the numbers together, and all the variables

-(9i-2(-2i+2))+35=0



We calculate terms in parentheses: -(9i-2(-2i+2)), so:

9i-2(-2i+2)

We multiply parentheses

9i+4i-4

We add all the numbers together, and all the variables

13i-4

Back to the equation:

-(13i-4)



We get rid of parentheses

-13i+4+35=0

We add all the numbers together, and all the variables

-13i+39=0

We move all terms containing i to the left, all other terms to the right

-13i=-39

i=-39/-13

i=+3

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