35=7/12z+14

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Solution for 35=7/12z+14 equation: 



35=7/12z+14

We move all terms to the left:

35-(7/12z+14)=0



Domain of the equation: 12z+14)!=0

z∈R



We get rid of parentheses

-7/12z-14+35=0

We multiply all the terms by the denominator


-14*12z+35*12z-7=0

Wy multiply elements

-168z+420z-7=0

We add all the numbers together, and all the variables

252z-7=0

We move all terms containing z to the left, all other terms to the right

252z=7

z=7/252

z=1/36

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