# 35=7/12z+14

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## Solution for 35=7/12z+14 equation:

35=7/12z+14
We move all terms to the left:
35-(7/12z+14)=0

Domain of the equation: 12z+14)!=0
z∈R

We get rid of parentheses
-7/12z-14+35=0
We multiply all the terms by the denominator

-14*12z+35*12z-7=0
Wy multiply elements
-168z+420z-7=0
We add all the numbers together, and all the variables
252z-7=0
We move all terms containing z to the left, all other terms to the right
252z=7
z=7/252
z=1/36

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