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35=5(x-3)+2x
We move all terms to the left:
35-(5(x-3)+2x)=0
We calculate terms in parentheses: -(5(x-3)+2x), so:We get rid of parentheses
5(x-3)+2x
We add all the numbers together, and all the variables
2x+5(x-3)
We multiply parentheses
2x+5x-15
We add all the numbers together, and all the variables
7x-15
Back to the equation:
-(7x-15)
-7x+15+35=0
We add all the numbers together, and all the variables
-7x+50=0
We move all terms containing x to the left, all other terms to the right
-7x=-50
x=-50/-7
x=7+1/7
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