35=4j-(-5-2j)

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Solution for 35=4j-(-5-2j) equation: 



35=4j-(-5-2j)

We move all terms to the left:

35-(4j-(-5-2j))=0

We add all the numbers together, and all the variables

-(4j-(-2j-5))+35=0



We calculate terms in parentheses: -(4j-(-2j-5)), so:

4j-(-2j-5)

We get rid of parentheses

4j+2j+5

We add all the numbers together, and all the variables

6j+5

Back to the equation:

-(6j+5)



We get rid of parentheses

-6j-5+35=0

We add all the numbers together, and all the variables

-6j+30=0

We move all terms containing j to the left, all other terms to the right

-6j=-30

j=-30/-6

j=+5

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