35=2x+2(4x-2)

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Solution for 35=2x+2(4x-2) equation: 



35=2x+2(4x-2)

We move all terms to the left:

35-(2x+2(4x-2))=0



We calculate terms in parentheses: -(2x+2(4x-2)), so:

2x+2(4x-2)

We multiply parentheses

2x+8x-4

We add all the numbers together, and all the variables

10x-4

Back to the equation:

-(10x-4)



We get rid of parentheses

-10x+4+35=0

We add all the numbers together, and all the variables

-10x+39=0

We move all terms containing x to the left, all other terms to the right

-10x=-39

x=-39/-10

x=3+9/10

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