35=10-(2x-5)

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Solution for 35=10-(2x-5) equation: 



35=10-(2x-5)

We move all terms to the left:

35-(10-(2x-5))=0



We calculate terms in parentheses: -(10-(2x-5)), so:

10-(2x-5)

determiningTheFunctionDomain
-(2x-5)+10

We get rid of parentheses

-2x+5+10

We add all the numbers together, and all the variables

-2x+15

Back to the equation:

-(-2x+15)



We get rid of parentheses

2x-15+35=0

We add all the numbers together, and all the variables

2x+20=0

We move all terms containing x to the left, all other terms to the right

2x=-20

x=-20/2

x=-10

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