35=0.35x2

Solution for 35=0.35x2 equation:

35=0.35x^2

We move all terms to the left:

35-(0.35x^2)=0

We get rid of parentheses

-0.35x^2+35=0

a = -0.35; b = 0; c = +35;
Δ = b2-4ac
Δ = 02-4·(-0.35)·35
Δ = 49
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{49}=7$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-7}{2*-0.35}=\frac{-7}{-0.7}
=+10
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+7}{2*-0.35}=\frac{7}{-0.7}
=-10
$