35=-10c+16+7(2c-3)

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Solution for 35=-10c+16+7(2c-3) equation: 



35=-10c+16+7(2c-3)

We move all terms to the left:

35-(-10c+16+7(2c-3))=0



We calculate terms in parentheses: -(-10c+16+7(2c-3)), so:

-10c+16+7(2c-3)

determiningTheFunctionDomain
-10c+7(2c-3)+16

We multiply parentheses

-10c+14c-21+16

We add all the numbers together, and all the variables

4c-5

Back to the equation:

-(4c-5)



We get rid of parentheses

-4c+5+35=0

We add all the numbers together, and all the variables

-4c+40=0

We move all terms containing c to the left, all other terms to the right

-4c=-40

c=-40/-4

c=+10

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