35=(q+1)(q-1)

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Solution for 35=(q+1)(q-1) equation: 



35=(q+1)(q-1)

We move all terms to the left:

35-((q+1)(q-1))=0

We use the square of the difference formula

q^2+1+35=0

We add all the numbers together, and all the variables

q^2+36=0

a = 1; b = 0; c = +36;
Δ = b2-4ac
Δ = 02-4·1·36
Δ = -144
Delta is less than zero, so there is no solution for the equation

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