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350=1/3x+2x
We move all terms to the left:
350-(1/3x+2x)=0
Domain of the equation: 3x+2x)!=0We add all the numbers together, and all the variables
x∈R
-(+2x+1/3x)+350=0
We get rid of parentheses
-2x-1/3x+350=0
We multiply all the terms by the denominator
-2x*3x+350*3x-1=0
Wy multiply elements
-6x^2+1050x-1=0
a = -6; b = 1050; c = -1;
Δ = b2-4ac
Δ = 10502-4·(-6)·(-1)
Δ = 1102476
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1102476}=\sqrt{4*275619}=\sqrt{4}*\sqrt{275619}=2\sqrt{275619}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1050)-2\sqrt{275619}}{2*-6}=\frac{-1050-2\sqrt{275619}}{-12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1050)+2\sqrt{275619}}{2*-6}=\frac{-1050+2\sqrt{275619}}{-12} $
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