35/49=5/n

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Solution for 35/49=5/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

35/49 = 5/n // - 5/n

35/49-(5/n) = 0

35/49-5*n^-1 = 0

-5*n^-1 = -5/7 // : -5

n^-1 = 1/7

-1 < 0

1/(n^1) = 1/7 // * n^1

1 = 1/7*n^1 // : 1/7

7 = n^1

n = 7

n = 7

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