35/42=5/n

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Solution for 35/42=5/n equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

35/42 = 5/n // - 5/n

35/42-(5/n) = 0

35/42-5*n^-1 = 0

-5*n^-1 = -5/6 // : -5

n^-1 = 1/6

-1 < 0

1/(n^1) = 1/6 // * n^1

1 = 1/6*n^1 // : 1/6

6 = n^1

n = 6

n = 6

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