35/(x-5)/(10/x)

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Solution for 35/(x-5)/(10/x) equation: 


D( x )

x-5 = 0

x = 0

10/x = 0

x-5 = 0

x-5 = 0

x-5 = 0 // + 5

x = 5

x = 0

x = 0

10/x = 0

10/x = 0

10*x^-1 = 0 // : 10

x^-1 = 0

x należy do O

x in (-oo:0) U (0:5) U (5:+oo)

(35/(x-5))/(10/x) = 0

35/(10*x^-1*(x-5)) = 0

35 = 0

x belongs to the empty set

x belongs to the empty set

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