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35-(2c+3)=2(c+6+c
We move all terms to the left:
35-(2c+3)-(2(c+6+c)=0
We add all the numbers together, and all the variables
-(2c+3)-(2(2c+6)+35=0
We get rid of parentheses
-2c-(2(2c+6)+35-3=0
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