35-(13-3x)=2(4x+1)

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Solution for 35-(13-3x)=2(4x+1) equation: 



35-(13-3x)=2(4x+1)

We move all terms to the left:

35-(13-3x)-(2(4x+1))=0

We add all the numbers together, and all the variables

-(-3x+13)-(2(4x+1))+35=0

We get rid of parentheses

3x-(2(4x+1))-13+35=0



We calculate terms in parentheses: -(2(4x+1)), so:

2(4x+1)

We multiply parentheses

8x+2

Back to the equation:

-(8x+2)



We add all the numbers together, and all the variables

3x-(8x+2)+22=0

We get rid of parentheses

3x-8x-2+22=0

We add all the numbers together, and all the variables

-5x+20=0

We move all terms containing x to the left, all other terms to the right

-5x=-20

x=-20/-5

x=+4

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