35(3x)(2x-20)=180

Solution for 35(3x)(2x-20)=180 equation:

35(3x)(2x-20)=180

We move all terms to the left:

35(3x)(2x-20)-(180)=0

We multiply parentheses

706x^2-7060x-180=0

a = 706; b = -7060; c = -180;
Δ = b2-4ac
Δ = -70602-4·706·(-180)
Δ = 50351920
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{50351920}=\sqrt{16*3146995}=\sqrt{16}*\sqrt{3146995}=4\sqrt{3146995}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-7060)-4\sqrt{3146995}}{2*706}=\frac{7060-4\sqrt{3146995}}{1412}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-7060)+4\sqrt{3146995}}{2*706}=\frac{7060+4\sqrt{3146995}}{1412}
$