35(20y-5)=12-27(14-42y)

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Solution for 35(20y-5)=12-27(14-42y) equation: 



35(20y-5)=12-27(14-42y)

We move all terms to the left:

35(20y-5)-(12-27(14-42y))=0

We add all the numbers together, and all the variables

35(20y-5)-(12-27(-42y+14))=0

We multiply parentheses

700y-(12-27(-42y+14))-175=0



We calculate terms in parentheses: -(12-27(-42y+14)), so:

12-27(-42y+14)

determiningTheFunctionDomain
-27(-42y+14)+12

We multiply parentheses

1134y-378+12

We add all the numbers together, and all the variables

1134y-366

Back to the equation:

-(1134y-366)



We get rid of parentheses

700y-1134y+366-175=0

We add all the numbers together, and all the variables

-434y+191=0

We move all terms containing y to the left, all other terms to the right

-434y=-191

y=-191/-434

y=191/434

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