34x2+13=34

Solution for 34x2+13=34 equation:

34x^2+13=34

We move all terms to the left:

34x^2+13-(34)=0

We add all the numbers together, and all the variables

34x^2-21=0

a = 34; b = 0; c = -21;
Δ = b2-4ac
Δ = 02-4·34·(-21)
Δ = 2856
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2856}=\sqrt{4*714}=\sqrt{4}*\sqrt{714}=2\sqrt{714}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-2\sqrt{714}}{2*34}=\frac{0-2\sqrt{714}}{68}
=-\frac{2\sqrt{714}}{68}
=-\frac{\sqrt{714}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+2\sqrt{714}}{2*34}=\frac{0+2\sqrt{714}}{68}
=\frac{2\sqrt{714}}{68}
=\frac{\sqrt{714}}{34}
$