34x+95=3(14x+9)34x+95=3(14x+9)

Solution for 34x+95=3(14x+9)34x+95=3(14x+9) equation:

34x+95=3(14x+9)34x+95=3(14x+9)

We move all terms to the left:

34x+95-(3(14x+9)34x+95)=0


We calculate terms in parentheses: -(3(14x+9)34x+95), so:

3(14x+9)34x+95

We multiply parentheses

1428x^2+918x+95

Back to the equation:

-(1428x^2+918x+95)


We get rid of parentheses

-1428x^2+34x-918x-95+95=0

We add all the numbers together, and all the variables

-1428x^2-884x=0

a = -1428; b = -884; c = 0;
Δ = b2-4ac
Δ = -8842-4·(-1428)·0
Δ = 781456
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{781456}=884$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-884)-884}{2*-1428}=\frac{0}{-2856}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-884)+884}{2*-1428}=\frac{1768}{-2856}
=-13/21
$